20y^2-y-32=0

Solution for 20y^2-y-32=0 equation:

20y^2-y-32=0

We add all the numbers together, and all the variables

20y^2-1y-32=0

a = 20; b = -1; c = -32;
Δ = b2-4ac
Δ = -12-4·20·(-32)
Δ = 2561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2561}}{2*20}=\frac{1-\sqrt{2561}}{40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2561}}{2*20}=\frac{1+\sqrt{2561}}{40}
$